### Problem Statement

The exponential function,

**EXP(x)**, is defined to be the sum of the following infinite series:Write a program that reads in a

**REAL**value and computes**EXP()**of that value using the series until the absolute value of a term is less than a tolerance value, say 0.00001.### Solution

! ---------------------------------------------------------

! This program computes exp(x) for an input x using the

! infinite series of exp(x). This program adds the

! terms together until a term is less than a specified

! tolerance value. Thus, two values are required:

! the value for x and a tolerance value. In this program,

! he tolerance value is set to 0.00001 using PARAMETER.

! ---------------------------------------------------------

PROGRAM Exponential

IMPLICIT NONE

INTEGER :: Count ! # of terms used

REAL :: Term ! a term

REAL :: Sum ! the sum of series

REAL :: X ! the input x

REAL, PARAMETER :: Tolerance = 0.00001 ! tolerance

READ(*,*) X ! read in x

Count = 1 ! the first term is 1 and counted

Sum = 1.0 ! thus, the sum starts with 1

Term = X ! the second term is x

DO ! for each term

IF (ABS(Term) < Tolerance) EXIT ! if too small, exit

Sum = Sum + Term ! otherwise, add to sum

Count = Count + 1 ! count indicates the next term

Term = Term * (X / Count) ! compute the value of next term

END DO

WRITE(*,*) 'After ', Count, ' iterations:'

WRITE(*,*) ' Exp(', X, ') = ', Sum

WRITE(*,*) ' From EXP() = ', EXP(X)

WRITE(*,*) ' Abs(Error) = ', ABS(Sum - EXP(X))

END PROGRAM Exponential

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### Program Input and Output

If the input value is 10.0, the following output shows that it requires 35 iterations to reach **EXP(10.0)=22026.4648**. Comparing the result with the one obtained from Fortran intrinsic function **EXP()**, the absolute error is zero.

After 35 iterations:

Exp(10.) = 22026.4648

From EXP() = 22026.4648

Abs(Error) = 0.E+0

If the input is -5.0, it takes 21 iterations to reach

**EXP(-5.0)=6.744734943E-3**. The value from using Fortran intrinsic function is 6.737946998E-3 and the absolute error is 6.787944585E-6.

After 21 iterations:

Exp(-5.) = 6.744734943E-3

From EXP() = 6.737946998E-3

Abs(Error) = 6.787944585E-6

### Discussion

- One obvious way of writing this program is computing each term
**directly**using the formula**x**. However, this is not a wise way, since both^{i}/i!**x**and^{i}**i!**could get very large when**x**or**i**is large. One way to overcome this problem is rewriting the term as follows:

Therefore, the (i+1)-th term is equal to the product of the i-th term and**x/(i+1)**. In the program, variable**Term**is used to save the value of the current term and is updated with

Term = Term * (X / Count)

where

**Count**is the value of**i**+1. - Variable
**Sum**is used to accumulate the values of terms. - Since the tolerance value is usually small, the first term whose value is 1 cannot be less than the tolerance value. Therefore, the computation starts with the second term and 1 is saved to
**Sum**. **Count**indicates which term is under consideration. Its plays the role of*i*in the infinite series shown above.- Since the computation starts with the first term, the value of the first term,
**x**, is saved to**Term**. - For each iteration, the absolute value of
**Term**is checked to see if it is less than the tolerance value**Tolerance**. If it is, the computation is done and**EXIT**. - Otherwise, this term is added to
**Sum**and prepare for the next term. Before this,**Count**is increased by one to point to the next term and consequently the next term is computed as**Term * (X / Count)**.